Question

kak bantuin ya kak please​

Answer 1

Verified answer

Penjelasan dengan langkah-langkah:

3. n(S)= 36

a. A = {(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}, n(A)=6

P(A)=6/36 = 1/6

b. B={(4,6),(5,5),(6,4)}, n(B)=3

P(B)=3/36=1/12

c. C={(5,6),(6,6)}, n(C)=2

P(C)=2/36=1/18

4. Peluang kejadian saling bebas

n(A)=1, P(A)=1/2

B={2, 3, 5}, n(B)=3, P(B)=3/6=1/2

P(A U B) = P(A) × P(B) = 1/2 × 1/2 = 1/4

5. Misalkan:

Cedera Berat = A

Cedera Ringan = B

Tidak Kecelakaan = C

a. Fh(A)=200×0,02 = 4 sopir

b. Fh(B)=200×0,04 = 8 sopir

c. P(C)= 1 - 0,02 - 0,04 = 0,94

Fh(C)=200×0,94 = 188 sopir