Penyelesaian:
No. 1
f (x) = (2x - 3) (-3x + 4)
f (x) = - 6x^2 + 17x - 12
f'(x) = - 12x + 17
No. 2
f (x) = (x^2 - 2x) (x - 5)
f (x) = x^3 - 7x^2 + 10
f'(x) = 3x^2 - 14x
No. 6
f (x) = 3/(x^2 - 4)
f'(x) = 0 (x^2 - 4) - 2x (3)/(x^2 - 4)^2
f'(x) = - 6x/(x^2 - 4)^2
No. 7
f (x) = 4x/(2x^3 - 5)
f'(x) = 4 (2x^3 - 5) - 6x^2 (4x)/(2x^3 - 5)^2
f'(x) = (8x^3 - 20 - 24x^3)/(2x^3 - 5)^2
f'(x) = - 16x^3 - 20/(2x^3 - 5)^2
No. 8
f (x) = 2x/(x + 1)
f'(x) = 2 (x + 1) - 1 (2x)/(x + 1)^2
f'(x) = (2x + 2 - 2x)/(x + 1)^2
f'(x) = 2/(x + 1)^2
====================
Kelas: 11
Mapel: Matematika
Bab: Turunan Fungsi Aljabar
Kode: 11.2.9
Kata Kunci: Turunan pertama
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Penyelesaian:
No. 1
f (x) = (2x - 3) (-3x + 4)
f (x) = - 6x^2 + 17x - 12
f'(x) = - 12x + 17
No. 2
f (x) = (x^2 - 2x) (x - 5)
f (x) = x^3 - 7x^2 + 10
f'(x) = 3x^2 - 14x
No. 6
f (x) = 3/(x^2 - 4)
f'(x) = 0 (x^2 - 4) - 2x (3)/(x^2 - 4)^2
f'(x) = - 6x/(x^2 - 4)^2
No. 7
f (x) = 4x/(2x^3 - 5)
f'(x) = 4 (2x^3 - 5) - 6x^2 (4x)/(2x^3 - 5)^2
f'(x) = (8x^3 - 20 - 24x^3)/(2x^3 - 5)^2
f'(x) = - 16x^3 - 20/(2x^3 - 5)^2
No. 8
f (x) = 2x/(x + 1)
f'(x) = 2 (x + 1) - 1 (2x)/(x + 1)^2
f'(x) = (2x + 2 - 2x)/(x + 1)^2
f'(x) = 2/(x + 1)^2
====================
Detil Jawaban
Kelas: 11
Mapel: Matematika
Bab: Turunan Fungsi Aljabar
Kode: 11.2.9
Kata Kunci: Turunan pertama