Question

Kak bantu kak tentang Integral
Semuanya kak :)​

Answer 1

Verified answer

Penjelasan dengan langkah-langkah:

IntegrAl

1) ʃ (3x²-1)⁴ . 6x dx

.... misal 3x²-1 = u

= 6 ʃ ⅙u⁴ du

= 6 ⅙.⅕u⁵

=⅕u⁵

= ⅕(3x²-1)⁵

= ⅕(3x²-1)⁵ + C

2) ʃ sin√x. 1/(2√x) dx

...... (dx = 1/u' → u = √x → u' = 1/(1/(2√x) )

= ʃ sin√x . 1/(2√x) . 1/(1/(2√x)

= ʃ sin√x . 1/(2√x) . 2√x

= ʃ sin√x dx

= -cos √x

3) ʃ sin³x - cos x dx

= ʃ sin³x dx - ʃ cos x dx

= ʃ sin²x.sinx dx - ʃ cos x dx

........ misal cos x = u

= -ʃ 1 du + ʃ u² du - sin x

= - u + ⅓u³ - sin x

= - cos x + ⅓cos³x - sin x

4) ʃ (2x+1)⁷ dx

= ½ ʃ (2x+1)⁷ dx

= ½.⅛ (2x+1)⁸

= 1/16 (2x+1)⁸