Question

Jwb Yg Bnr Ya, Pke Cra Teorema Pythagoras

Answer 1

1) AC² = CD x CB
CD = AC²/CB = 12² / 16 = 8

2) AD² = CD x DB
AD² = 5 x 10
AD² = 50
AD = √50 = 5√2

3) KL²  = LN x LM
KL² = (20-8) x (20)
KL² = 12(20) = 240
KL = √240 = 4√15

4) BC² =  CD x CA
CD = BC²/CA
CD = 6² / 10 = 36/10  = 3,6

BD² = CD x AD
BD² = (3,6)(10-3,6)
BD² = (3,6) (6,4) = 23,04
BD = √23,04 
BD= 0,48