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(a + (4 - 1)b) + (a + (5 - 1)b) = 55
2a + 3b + 4b = 55
⇒ 2a + 7b = 55
(a + (9 - 1)b) - 2(a + (2 - 1)b) = 1
(a + 8b) - 2(a + b) = 1
⇒ -a + 6b = 1
Eliminasi
2a + 7b = 55 (x1)
-a + 6b = 1 (x2)
⇒
2a + 7b = 55
-2a + 12b = 2
------------------------- +
⇒ 19b = 57
b = 3
Subtitusi
-a + 6b = 1
-a + 6(3) = 1 ⇒ a = 17