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sn = n/2 (2a + (n-1)b)
s6 = 6/2 (2a + (6-1)b) = 120
= 3 (2a + 5b) = 120
= 6a + 5b =120
s7 = 7/2 (2a + (7-1)b) = 133
= 7/2 (2a + 6b) = 133
= 7/2 (2a+ 6b) = 133
= 7a + 21b = 133
6a + 5b =120
7a + 21b = 133
ini dpt diselesaikan dengan metode elimanasi atau gabungan