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x.y=4
(a+b)²=?
jwb
(a+b)²=(a+b)(a+b)
6²=a(a+b)+b(a+b)
36=a²+ab+ab+b²
36=a²+2a.b+b²
36=a²+2.4+b²
36=a²+b+b²
36-8 = a²+b²
28=a²+b²
x1 + x2 = 6,
x1.x2 = 4
ditanya: jumlah kuadrat bilangan tersebut
(x1+x2)² = x1² + 2x1x2 + x2²
(x1+x2)² - 2x1x2 = x1² + x2²
6² - 2.4 = x1² + x2²
36 - 8 = x1² + x2²
28 = x1² + x2²
semoga bermanfaat