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Verified answer
X + y = 12...=> y = 12 - xx^2y = x^2( 12 - x )
= 12x^2 - x^3
f(x) = 12x^2 -x^3
f'(x) = 24x - 3x^2
maksimum untuk f'(x) = 0
24x - 3x^2 = 0
3x ( 8 - x ) = 0
x = 0 atau x = 8
Jadi x^2y maksimum untuk x = 8