Jumlah bilangan-bilangan ganjil 3+5+7+...+k=440,maka k= ...... a.20 b.22 c.41 d.256 dengan caranya
Takamori37
Dengan deret aritmatika: a = 3 b = 2 Sn = 440 Maka, Karena n harus positif, maka: n = 20 Sehingga, k = a+(n-1)b k = 3+(20-1)2 k = 3 + (19 x 2) k = 3 + 38 k = 41
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marsyaaulia11
A = 3 b = 2 = 440 = 440 = 440 = 440 = 440 = 880 = 0 = -880 0 = -440 0 = (n+22)(n-20) *n+22=0 n = -22 ( tidak mungkin karena min) *n-20 = 0 n = 20
a = 3
b = 2
Sn = 440
Maka,
Karena n harus positif, maka:
n = 20
Sehingga,
k = a+(n-1)b
k = 3+(20-1)2
k = 3 + (19 x 2)
k = 3 + 38
k = 41
b = 2
440 =
440 =
440 =
440 =
880 =
0 =
0 =
0 = (n+22)(n-20)
*n+22=0
n = -22 ( tidak mungkin karena min)
*n-20 = 0
n = 20