jwb
an = a1 + (n-1)d
sn = n/2 (a1 + an)
a18 = 2 + (18-1)2 (suku ke-n)
= 2 + 34
= 36
S18 = 18/2 (2 + 36)
= 9 x 38
= 342
jumlah 18 suku pertama deret aritmatika = 342
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jwb
an = a1 + (n-1)d
sn = n/2 (a1 + an)
a18 = 2 + (18-1)2 (suku ke-n)
= 2 + 34
= 36
S18 = 18/2 (2 + 36)
= 9 x 38
= 342
jumlah 18 suku pertama deret aritmatika = 342