Question

Jumlah 16 suku pertama dari deret 3+6+12 adalah

Answer 1

3,6,12,...
deret geo
a= 3
r = 2

s16 = a(r¹⁶ -1)/(r-1)
s16 = 3(2¹⁶ -1)/(2-1)
s16 = 3(32.767)/(1)
s16 = 98.301

Answer 2

Diketahui :
a = 3
r = 2

S6 = a(r⁶ -1)/(r-1)
S6 = 3(2⁶ -1)/(2-1)
S6 = 3(64-1)/1
S6 = 3 (63) / 1
S6 = 189/1
S6 = 189

Smoga membantu kakak