Jle gramów chlorku sodu otrzymanego po odparowaniu do sucha 30g roztworu 6%
Cp=6%
mr=30g
ms=?
Cp=ms*100%/mr
ms=Cp*mr/100%
ms=6*30/100
ms = 1,8g NaCl
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Cp=6%
mr=30g
ms=?
Cp=ms*100%/mr
ms=Cp*mr/100%
ms=6*30/100
ms = 1,8g NaCl