Question

Jika x=akar 6 + akar 3,y=akar 8 - akar 2,maka x.y adalah

Answer 1

(√6+√3)(√8-√2)
= √48 - √12+√24-√6
= 4√3-2√3+2√6-√6
= 2√3+√6

Answer 2

Xy = (√6+√3) x (√8-√2) = (√48-√12+√24-√6) = 4√3 - 2√3 + 2√6 - √6 = 2√3+√6