Question

Jika (x^2 + 2) (3x^2 + 3x -1) = ax^4 + bx^3 + cx^2 + dx +e maka nilai a + e adalah (tolong pakai cara)

Answer 1

( x^2 + 2 ) (3x^2 + 3x -1 ) = ax^4 + bx^3 + cx^2 + dx + e
3x^4 + 3x^3 -x^2 + 6x^2 + 6x -2 = ax^4 + bx^3 + cx^2 + dx + e
3x^4 + 3x^3 + 5x^2 + 6x -2 = ax^4 + bx^3 + cx^2 + dx + e

nilai a
3x^4 = ax^4
a = 3

nilai e
e = -2

a + e = 3 + (-2) = 1