Question

Jika x1 dan x2 adalah akar-akar persamaan kuadrat 2x^2 + 4x - 3 =0 . Maka nilai x1^3 . x2 + x1 . x2^3 adalah ..

Answer 1

2x² + 4x - 3 = 0
x₁+x₂ = -b/a = -4/2 = -2
x₁.x₂ = c/a = -3/2

x₁³.x₂ + x₁.x₂³ = x₁.x₂ ( x₁² + x₂²)
                     = x₁.x₂ [(x₁+x₂)² - 2x₁.x₂]
                     = (-3/2) [(-2)² - 2(-3/2)]
                     = (-3/2) [4+3]
                     = (-3/2) x 7
                     = -21/2

semoga membantu ya :)