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sin x = a
cos x = b
3ab - a - 6b + 2 = 0
faktorkan
a + 6b - 3ab - 2 = 0
(a-2 ) (1-3b ) = 0
a = 2
sin x = 2 , salah , karena -1<sin x < 1
1 - 3b = 0
3b = 1
b = 1/3
cos x = 1/3 , benar , karena -1 < cos x < 1
sin x = √(1 - cos²x)
= √(1 - (1/3)²)
= √(8/9)
= 2/3 √2
cos 2x = cos²x - sin²x
= (1/3)² - (2/3 √2)²
= 1/9 - 4/9 (2)
= 1/9 - 8/9
= -7/9