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y = 3
3.-2 + 2.3 =
-6 + 6 = 0
2x-3y=-13 dikali5=10x-15y=-65
5x+2y=-4 dikali2=10x+4y=-8
-19y=-54
y=-54
-19
y=3
eliminasi variabel y
2x-3ya=-13 dikali2=4x-6y=-26
5x+2y=4 dikali3=15x+6y=-12
-19x=-38
x=-2
3x+2y=-6+6=0