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Misalkan:rusuk kubus besar = x
rusuk kubus kecil = y
luas permukaan kubus besar = 6x²
luas permukaan kubus kecil = 6y²
x - y = 3 → x = 3 + y ...pers.1
6x² - 6y² = 234 ...pers.2
Substitusikan pers.1 ke pers.2
6(3 + y)² - 6y² = 234
6(9 + 6y + y²) - 6y² = 234
54 + 36y + 6y² - 6y² = 234
54 + 36y = 234
36y = 234 - 54
36y = 180
y = 180 ÷ 36
y = 5 cm
x - y = 3
x - 5 = 3
x = 3 + 5
x = 8 cm
Luas permukaan kubus kecil = 6y²
= 6 × 5²
= 6 × 25
= 150 cm² (B)