Jika sebuah sumber suara yang berjarak 90 meter menghasilkan intensitas bunyi sebesar 1*10-3 berapak.... Question from @syafingial

October 2018 2 30 Report

Jika sebuah sumber suara yang berjarak 90 meter menghasilkan intensitas bunyi sebesar 1*10-3 berapakah taraf intensitas bunyi pada jarak 1800meter

tiaratfe Dik : Io = 10^-12

TI = 10 log (10^-3/10^-12) = 10 log 9 = 10 . 9 = 90
TI2 = TI - 20 log (r2/r1) = 90 - 20 log (1800/90) = 90 - 20 log 20 = 90 - 26 = 64

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izharulhaq78 $\displaystyle I_o=10^{-12}\,\text{W}/\text{m}^2\\r_1=90\,\text{m}=r\\I_1=1\cdot10^{-3}\,\text{W}/\text{m}^2\\r_2=1800\,\text{m}=20r\\\\T_{I2}=?\\\\T_{I1}=10(\log I-\log I_o)\\T_{I1}=10(\log 10^{-3}-\log 10^{-12})\\T_{I1}=10(-3-[-12])\\T_{I1}=10(-3+12)\\T_{I1}=10(9)\\T_{I1}=90\,\text{dB}\\\\T_{I2}=T_{I1}-20\log\left(\frac{r_2}{r_1}\right)\\T_{I2}=90-20\log\left(\frac{20r}{r}\right)\\T_{I2}=90-20\log20\\T_{I2}=90-20\times1,3\\T_{I2}=90-26\\\boxed{\boxed{T_{I2}=64\,\text{dB}\text{ atau }6,4\,\text{B}}}$

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