Question

Jika PS = (n + 6)cm, SR = (2N + 2)cm, OP = n cm, dan OR = (2N-2) cm, keliling PQRS = ... cm

Answer 1

(OS)^2=(SP)^2 - (OP)^2
(OS)^2=(SR)^2 - (OR)2

(n+6)^2 - (n)^2 = (2n+2)^2 - (2n-2)^2
n^2 + 12n +36 - n^2 = ( 4n^2 + 8n + 4) - (4n^2 - 8n +4)
12n + 36 = 16n
36 = 4n
n = 9

keliling = 6n +16 = 54 + 16 = 70cm