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α baja = 0,000012/°C
P = 50 cm
L = 10 cm
ΔT = 40°C
ditanya : pertambahan luas (ΔA)
β = 2α
β = 2(0,000012) = 0,000024/°C
A₀ = P x L =50 x 10 =500 cm²
ΔA = A₀βΔT
ΔA = 500(0,000024)(40)
ΔA = 0,48 cm²