November 2019 2 106 Report
Jika \int\limits^b_a {\frac{x+1}{x-1}} \, dx=p , maka \int\limits^b_a {\frac{2x}{x-1}} \, dx= ....
(A) b-a+p
(B) b+a+p
(C) b-a-p
(D) a-b-p
(E) a-b+p
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