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n = 2a - 1
= 4m - 2n
= 4 ( 2a + 3 ) - 2 ( 2a - 1 )
= 8a + 12 - 4a + 2
= 8a - 4a + 12 + 2
= 4a + 14
n = 2a - 1
4m - 2n = ?
substitusi
4(2a+3) - 2(2a-1)
8a + 12 - 4a + 2
Hasil = 4a + 14 (B.)