aryakusuma2000
JIKA 3 LOG 4 = a dan 7 LOG 3 = B,MAKA NILAI 28 LOG 108: 28 log 108= log 108 log 28 =3 log 108 3 log 28 =3 log (4.3.3.3) 3 log (7.4) = 3 log 4 + 3 log 3 + 3 log 3 + 3log 3 = a +1+1+1 =a +3 =ab +3b 3 log 7 + 3 log 4 1/b +a 1/b+a 1 + ab cara ini dilakukan sesuai sifat logaritma yaitu a log b = n log b . n log a
28 log 108= log 108
log 28
=3 log 108
3 log 28
=3 log (4.3.3.3)
3 log (7.4)
= 3 log 4 + 3 log 3 + 3 log 3 + 3log 3 = a +1+1+1 =a +3 =ab +3b
3 log 7 + 3 log 4 1/b +a 1/b+a 1 + ab
cara ini dilakukan sesuai sifat logaritma yaitu a log b = n log b .
n log a