Question

Jika ⁴log3= x, ⁴log5=y, ⁴log8=z
hitunglah
⁴log15+⁴log8=

⁴log20-⁴log15=

Answer 1

⁴log 15 + ⁴log 8
= (⁴log 3 + ⁴log 5) + 3/2
= x + y + z

⁴log 20 - ⁴log 15
= (⁴log 4 + ⁴log 5) - (⁴log 3 + ⁴log 5)
= (1 + y) - (x + y)
= 1 - x

Answer 2

⁴log 15+⁴log8
= ⁴log 5.3+⁴log8
= ⁴log 5+⁴log 3+⁴log8
= y+z+x

⁴log20-⁴log15
= ⁴log5.4 - ⁴log 5.3
= ⁴log5+⁴log4 - ⁴log 3+⁴log 5
= y+1 - x+y
= 2y-x+1