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maka 2logx = 1+3log(x+y)
substitusi ke persamaan pertama
2logx+3log(x+y)=5
1+3log(x+y)+3log(x+y)=5
2 x 3log(x+y)=4
3log(x+y)=4/2
3log(x+y)=2
(x+y)=9
mudah mudahan bisa dimengerti