Question

jika log 2 = m dan log 3 = n log 216 =

Answer 1

Log 216 = log 2^3 x 3^3
           = log2^3 + log3^3
           = 3m + 3n
           = 3(m+n)

Answer 2

Log 216 = log 6³ = 3 · log 6

3 · log 6 = 3 · (log 2 + log 3)
              = 3 · (m + n)
 log 216 = 3m + 3n