Question

Jika log 2 = 0,3010
log 3 = 0,4771
hitunglah :
a. log 12
b. log 0,6

Answer 1

Jabarkan :
log 12
= log (4 x 3)
= log 4 + log 3
= log 2² + log 3
= 2(log 2) + log 3
= 2(0,3010) + 0,4771
= 0,6020 + 0,4771
= 1,0791


log 0,6
= log (6 x 0,1)
= log 6 + log 0,1
= log 6 + log (1/10)
= log 6 + log (10⁻¹)
= log 6 - log 10
= log 6 - 1
= log (2 x 3)  - 1
= log 2 + log 3 - 1
= 0,3010 + 0,4771 - 1
= 0,7781 - 1
= - 0,2219

Answer 2

Log 12 = log 2. log 3. log 2
= log (2+3+2)
=log ( 0,3010+0,4771+ 0,3010)
=1,0791