Question

Jika log 2 = 0,3010 , log 3 = 0,4771 , dan log 5 = 0,6990 ,maka nilai dari ²log 6+ ² log 8 adalah

Answer 1

2^log6×8 = 2^log48=log48/log2
log 3×2×2×2×2 / log2
log3+ 4. log2 / log2
0,4771+ 4. 0,3010 / 0,3010
0,4771+ 1,2040 / 0,3010
1,6811 / 0,3010
5,5850