Question

Jika Ksp Mg(OH)2 pada suhu 25°C = 4 × 10–¹² .tentukan PH larutan tersebut!

Answer 1

Ksp= [Mg2+] [2OH-]^2
4.10^-12 = S . (2S)^2
4.10^-12 = 4S^3
S= 10^-4

OH-= 2S = 2.10^-4

pOH= -log[OH-]
pOH= -log 2.10^-4
pOH= 4-log 2
pH= 10+log 2