Question

jika kemudian lilin digeser 8 cm menjauhi lensa cembung, maka jarak bayangannya menjadi​

Answer 1

jarak fokus :

1/f = 1/s + 1/s'

1/f = 1/20 + 1/20

1/f = 2/20

1/f = 20/2

1/f = 10/1

1/f = 10 cm

maka cari jarak bayangan 8 cm :

1/f = 1/s + 1/s'

1/10 - 1/12 + 1/s'

( 1 × 6 )/( 10 × 6 ) - ( 1 × 5 )/( 12 × 5 ) = 1/s'

6/60 - 5/60 = 1/s'

1/60 = 1/s'

60/1 = s'/1

60 = s'

JIKA DITANYA SIFAT BAYANGAN :

NYATA TERBALIK DAN DI PERBESAR