Question

Jika Ka=10 pangkat min 5, cari pH CH3COOH 0,01 m??

Answer 1

[H+] = akar Ka . Ca
[H+] = akar 10^-5 . 10^-2
[H+] = akar 10^-7
[H+] = 10^-3,5

pH = - log [H+]
pH = 3,5

CH3COOH termasuk asam lemah

Answer 2

CH3COOH ⇔ CH3COO⁻ + H⁺
0,01 mol

Ka= [CH3COO⁻][H⁺] / [CH3COOH]
10⁻⁵ = [H⁺]² / [0,01]
[H⁺] =√ 10⁻⁵ . 0,01 = √ 10⁻⁷ =3.16 . 10⁻⁶

pH = - log [H⁺]
     = - log [3.16 .10⁻⁶]
     = 6 - log 3.16 = 5.5

semoga membantu ;)