Question

Jika garis 3ax – ( b – 2 )y + 4 = 0 berhimpit dengan garis 6x – 3ay + 4 = 0, hitunglah nilai dari 2a + b

Answer 1

Berarti :
3ax - by + 2y = -4 --> 6x -3ay = -4
3a(x) = 6(x)
3a = 6
a = 2

-by + 2y = -3ay
-(b-2)y = (-3a)y
-b + 2 = -3(2)
-b +2 = -6
-b = -8
b = 8

jadi :
2a + b = 2(2) + 8 = 4+8 = 12