Question

jika f(x)=(x-1) (x+2) (x+3),maka f'(1)..​

Answer 1

jwb

f(x) = (x-1)(x+2)(x+3) (turunan fungsi)

f'(x) = (x+2)(x+3) + (x-1)(x+3) + (x-1)(x+2) (fungsi komposit)

= x^2 + 5x + 6 + x^2 + 2x - 3 + x^2 + x - 2

= 3x^2 + 8x + 1

f'(1) = 3(1)^2 + 8(1) + 1

= 3 + 8 + 1

= 12

f'(1) = 12 opsi (C)