Question

Jika f(x)=-x²+2x-1 maka f(2t) dan f(2√x) adalah?​

Answer 1

Jawab:

f(2t) = -(4t²) + 4t - 1

dan

f(2√x) = -(4x²) + 4√x - 1

Penjelasan dengan langkah-langkah:

f(x) = -x² + 2x - 1

>> f(2t)

f(x) = -x² + 2x - 1

f(2t) = -(2t)² + 2(2t) - 1

f(2t) = -(4t²) + 4t -1

>>f(2√x)

f(x)= -x² + 2x - 1  

f(2√x) = -(2√x)² + 2(2√x) - 1

f(2√x) = -(4x²) + 4√x - 1

Answer 2

Jawab:

f(2t) = -(4t^2) + 4t - 1  dan f(2√x) = -(4x^2) + 4√x - 1

Penjelasan dengan langkah-langkah:

f(x)=-x^2+2x-1

f(2t)=-(2t)^2+2(2t)-1

f(2t)=-4t^2+4t-1

f(2√x)=-(2√x)^2+2(2√x)-1

f(2√x)=-4x^2+4√x-1