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Verified answer
F'(x) = (x - 2)(x - 4)f'(x) = x² - 4x - 2x + 8
f'(x) = x² - 6x + 8
Integralkan
int x² - 6x + 8
= 1/3 (x³) - (6/2) x² + 8x + C
f(x) = 1/3 (x³) - 3x² + 8x + C
1/3 (3³) - 3(3²) + 8(3) + C = 1
1/3 (27) - 3(9) + 24 + C = 1
9 - 27 + 24 + C = 1
6 + C = 1
C = -5
f(x)
= 1/3 (x³) - 3x² + 8x - 5