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f(x) = (3x-5)/(2x+1) = (ax+b)/(cx+d)
rumus f-¹(x) = (-dx+b)/(cx-a)
=> f-¹(x) = (-x-5)/(2x-3)
=> f-¹(0) = [-(0)-5]/[2(0)-3]
=> f-¹(0) = 5/3 = 1⅔ = 1,67
Silahkan dicek kembali