Question

Jika f(x) = 1 per 243 dikali 3 pangkat 4x + 1 maka f(3) = ....

Answer 1

F(x) = 1/243.3^(4x+1)
f(3) = 1/243.3^(4.3+1)
f(3) = 1/3^5.3^13
f(3) = 3^13/3^5
f(3) = 3^8
f(3) = 6561