Question

Jika diketahui nilai hambatan R₁ = 2, R₂ = 3, R3 = 6, R4=4, R5 = 4. Hitunglah:

a. Hambatan pengganti (R tot)
b. Arus listrik yang mengalir pada rangkaian (I)
c. Arus listrik dan tegangan listrik pada resistor R1
d. Arus listrik dan tegangan listrik pada resistor R2
e. Arus listrik dan tegangan listrik pada resistor R3
f. Arus listrik dan tegangan listrik pada resistor R4
g. Arus listrik dan tegangan listrik pada resistor R5​

Answer 1

Rangkaian Seri Paralel

a.

R pengganti R2 dan R3 (Rp1)

Rp1 = R2 × R3 / (R2 + R3)

Rp1 = 3 × 6/(3 + 6)

Rp1 = 2 ohm

R pengganti R4 dan R5 (Rp2)

Rp2 = R4 × R5 / (R4 + R5)

Rp2 = 4/2

Rp2 = 2 ohm

R total (Rt)

Rt = R1 + Rp1 + Rp2

Rt = 2 + 2 + 2

Rt = 6 ohm

b.

Arus pada rangkaian (I)

= V/Rt

= 12/6

= 2 A

c.

Arus pada R1 = I rangkaian = 2 A

Tegangan pada R1 = VR1 = I × R1 = 2 × 2 = 4 V

d.

Arus pada R2 = I2

I2 = 6/(3 + 6) × I = 6/9 × 2 = 1,33 A

VR2 = I2 × R2 = 1,33 × 3 = 3,99 V

e.

I3 = 3/(3 + 6) × I = 1/3 × 2 = 2/3 = 0,67 A

VR3 = I3 × R3 = 2/3 × 6 = 4 V

f dan g.

I4 = I5 = I/2 = 2/2 = 1 A

VR4 = VR5 = I4 × R4 = 1 × 4 = 4 V

Answer 2

1)

RP (R1)

1/RP = 1/R2 + 1/R3

= 1/3 + 1/6

= 2/6 + 1/6

= 3/6

= 6/3

= 2 OHM

RP (R2)

1/RP = 1/R4 + 1/R5

= 1/4 + 1/4

= 2/4

= 4/2

= 2 OHM

MAKA :

RT = (2 + 2 + 2)OHM

= (4 + 2(OHM)

= 6 OHM

2) I = V/RT

= 12/6

= 2/1

= 2A

3) V = I(R1)

= (2(2)V

= 4 V

4) I2 :

= 6/9(2)

= 6(2)/9

= 12/9

= 4/3

= 1,33 A

V :

= (1,33(3)V

= 3,99 V

5) I3 :

= 3/9(2)

= 3(2)/9

= 6/9

= 2/3

= 0,67 A

V :

= 2/3(6)

= 2(6)/3

= 12/3

= 4/1

= 4 V

5) I ÷ 2

= 2 ÷ 2

= 1A

6) V = I(R)

= 1(4)

= 4 V