Jika diketahui massa atom relatic dari atom unsur H = 1 : N = 4 : S = 32 : AI = 27 : O = 16. Cu = 63 hitunglah massa molekul relatif (MR) dari senyawa berikut:
A.(NH4)2 SO4
B.Cu SO4 . 5H2O
A.(NH4)2 SO4
B.Cu SO4 . 5H2O
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Jawaban:
Penjelasan:
a. Mr (NH₄)₂SO₄= 2 x (Ar N + 4(Ar H)) + Ar S + 4(Ar O)
= 2 x (14 + 4(1)) + 32 + 4(16)
= 2 x (18) + 32 +48
= 36+32+48
= 116
b. Mr CuSO₄.5H₂O = Ar Cu+Ar S+4(Ar O) + 5(2(Ar H)+Ar O)
= 63 + 32 + 4(16) + 5(2(1) + 16)
= 63 + 32 + 48 + 5(18)
= 63 + 32 + 48 + 90
= 233