Question

Jika diketahui Ksp SrSO4 = 1,6 × 10-7 massa SrSo4 yang terlarut dalam larutan jenub SrSO4 sebesar...(Mr SrSO4 =184)

Answer 1

SrSO4 -> Sr 2+ + SO4 2- s mol/L. s mol/L. s mol/L Ksp SrSO4 = [Sr 2+] [SO4 2-] = s. s 1,6 x 10-7 = s2 S = √16 x 10-8 = 4 x 10-4 M Massa = M x Mr = 4 x 10-4 x 184 = 73,6 mg