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[OH⁻] = Kw/Ka [garam].valensi
= 10⁻¹⁴/10⁻⁵.10⁻¹.2
= 10⁻¹⁰.2
= 10⁻⁵
pOH = -log [10⁻⁵]
= 5 - log
pH = 14 - (5 - log )
= 9 + log
= 9 + 0,15 = 9,15