Question

Jika diketahui Ar Ca = 40 , C = 12 , O = 16 dan bilangan avogadro = 6,02 x 1023 , maka 50 gram CaCO₃ mempunyai jumlah molekul ?

Answer 1

Mr CaCO3 = 100
n=a/M
n=50/100=1/2 mol
jml molekul=n * 6,02*10 ^23=1/2*6,02*10^23=3,01*10^23 
   

Answer 2

Mr CaCO3=40+12+(3x16)=100
n CaCO3=gr/Mr= 50/100=1/2 mol
x CaCO3=1/2 x 6,02x10^23=3,01 x 10^23 molekul