Question

Jika diketahui a=6 dan b=3 maka tentukan nilai aljabar dibawah ini
a. a^2- 2ab + b^2
b.2ab - a^2b + b^3
c.3a^2 - 4ab^2 +ab
d.(4a+1)(a^2 -7b)

Answer 1

A.
6^2 - 2(6)(3) + 3^2
= 36 - 36 + 9
= 9

b. 2(6)(3) - 6^2(3) + 3^3
= 36 - 36(3) + 27
= 36- 108 +27
= -45

c.
3(6)^2 - 4(6)(3)^2 + (6)(3)
= 3(36) - 24(9) + 18
= 108 -216 + 18
= -90

4.
(4(6) + 1) (6^2 - 7(3)
=(24+1) (36-21)
= 25 × 15
=375