Question

Jika diketahui 7 log2=a,2log3=b maka nilai 6log98

Answer 1

^7log 2 = a
^2log 3 =  b

^6log 98 = (^2log 98)  /  (^2log 6)
= (^2log 2 . 7^2) / (^2log 2 . 3)
= ( ^2log 2 + ^2log 7^2 )  / (^2log  2 + ^2log 3)
= (1 + 2 (1/^7log 2)) / (1 + b)
= (1 +  2(1/a)) / (1 + b)
= (1 + 2/a) / (1+ b)
= (a + 2) / (a + ab)