Question

Jika alfa dan beta persamaan kuafratx²+5x-6=0 tentukan akarnya alfa-3dan beta-3

Answer 1

Alfa = x1
beta = x2
x²+5x-6=0
(x-1)(x+6)=0
x=1 atau x=-6
alfa = √1-3 = √ -2
beta = √ -6 -3 = √-9 = -3