Question

Jika a=5 dan b=2, maka nilai dari a3 – 3a2b + 3ab2 – b3 =

Answer 1

(a-b)3 = a3-3a2b+3ab2-b3
(5-2)3 = (3)3 = 27

Answer 2

A = 5
b = 2

a^3 - 3a^2b + 3ab^2 - b^3 
= (5^3) - (3 x 5^2 x 2) + (3 x 5 x 2^2) - (2^3)
= 125 - 150 + 60 -8
= 27