Question

Jika a dan b akar persaman kuadrat 2×-6×+1=0 persamaan kuadrat baru yang akar nya (a + 3 ) dan ( b + 3 ) asdalah..

Answer 1

X2-(a+3+b+3)x + (a+3)(b+3)
= x2-(a+b+6)x + (ab+3a+3b+9)
= x2-(-b/a+6)x + (c/a+3(-b/a)+9)
= x2-(3+6)x + (1/2+3(3)+9)
= x2-9x+37/2
dikali 2
= 2x2-18x+37