Jika A=[■(-1&1&[email protected]&-1&0)], B=[■(a&[email protected]&[email protected]&0)] dan AB=[■(4&[email protected]&0)], maka nilai c-a adalah …
Takamori37
![A= \left[\begin{array}{ccc}-1&1&2\\-1&-1&0\end{array}\right], B=\left[\begin{array}{cc}a&-1\\b&1\\c&0\end{array}\right] \\ \\ AB=\left[\begin{array}{cc}4&2\\2&0\end{array}\right] \\ \\ AB=AB \\\\ \left[\begin{array}{cc}4&2\\2&0\end{array}\right]=\left[\begin{array}{cc}-a+b+2c&1+1+0\\-a-b&1-1+0\end{array}\right] \\\\ \left[\begin{array}{cc}4&2\\2&0\end{array}\right]=\left[\begin{array}{cc}-a+b+2c&2\\-a-b&0\end{array}\right] \\\\ -a+b+2c=4 \\ -a-b=2 \\ --$Jumlah$-- \\ -2a+2c=6 \\ 2c-2a=6 \\ 2(c-a)=6 \\ c-a=3](https://tex.z-dn.net/?f=A%3D+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%261%262%5C%5C-1%26-1%260%5Cend%7Barray%7D%5Cright%5D%2C+B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26-1%5C%5Cb%261%5C%5Cc%260%5Cend%7Barray%7D%5Cright%5D+%5C%5C+%5C%5C+AB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D4%262%5C%5C2%260%5Cend%7Barray%7D%5Cright%5D+%5C%5C+%5C%5C+AB%3DAB+%5C%5C%5C%5C+%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D4%262%5C%5C2%260%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-a%2Bb%2B2c%261%2B1%2B0%5C%5C-a-b%261-1%2B0%5Cend%7Barray%7D%5Cright%5D+%5C%5C%5C%5C+%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D4%262%5C%5C2%260%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-a%2Bb%2B2c%262%5C%5C-a-b%260%5Cend%7Barray%7D%5Cright%5D+%5C%5C%5C%5C+-a%2Bb%2B2c%3D4+%5C%5C+-a-b%3D2+%5C%5C+--%24Jumlah%24--+%5C%5C+-2a%2B2c%3D6+%5C%5C+2c-2a%3D6+%5C%5C+2%28c-a%29%3D6+%5C%5C+c-a%3D3 "A= \left[\begin{array}{ccc}-1&1&2\\-1&-1&0\end{array}\right], B=\left[\begin{array}{cc}a&-1\\b&1\\c&0\end{array}\right] \\ \\ AB=\left[\begin{array}{cc}4&2\\2&0\end{array}\right] \\ \\ AB=AB \\\\ \left[\begin{array}{cc}4&2\\2&0\end{array}\right]=\left[\begin{array}{cc}-a+b+2c&1+1+0\\-a-b&1-1+0\end{array}\right] \\\\ \left[\begin{array}{cc}4&2\\2&0\end{array}\right]=\left[\begin{array}{cc}-a+b+2c&2\\-a-b&0\end{array}\right] \\\\ -a+b+2c=4 \\ -a-b=2 \\ --$Jumlah$-- \\ -2a+2c=6 \\ 2c-2a=6 \\ 2(c-a)=6 \\ c-a=3")
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