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B transpose = 4
1
3
BA= -4 8 12
-1 2 3
-3 6 9
det (BA)= -4 [2 3] -8 [-1 3] +12 [-1 2]
[6 9] [-3 9] [-3 6]
= -4(0) -8(0) + 12(0)
= 0